<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:content="http://purl.org/rss/1.0/modules/content/"><channel><title>LeetCode 108 on Jeanphilo Blog</title><link>https://shio-chan-dev.github.io/jeanblog/zh/tags/leetcode-108/</link><description>Recent content in LeetCode 108 on Jeanphilo Blog</description><generator>Hugo -- 0.161.1</generator><language>zh-cn</language><lastBuildDate>Mon, 20 Apr 2026 09:37:25 +0800</lastBuildDate><atom:link href="https://shio-chan-dev.github.io/jeanblog/zh/tags/leetcode-108/index.xml" rel="self" type="application/rss+xml"/><item><title>Hot100：将有序数组转换为二叉搜索树（Convert Sorted Array to Binary Search Tree）分治选中点 ACERS 解析</title><link>https://shio-chan-dev.github.io/jeanblog/zh/alg/leetcode/hot100/binary-tree/108-convert-sorted-array-to-binary-search-tree/</link><pubDate>Mon, 20 Apr 2026 09:37:25 +0800</pubDate><guid>https://shio-chan-dev.github.io/jeanblog/zh/alg/leetcode/hot100/binary-tree/108-convert-sorted-array-to-binary-search-tree/</guid><description>围绕 LeetCode 108 讲清为什么每次选中点就能同时满足 BST 有序性和平衡性，以及索引分治写法为什么最稳定。</description></item></channel></rss>