<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:content="http://purl.org/rss/1.0/modules/content/"><channel><title>后序遍历 on Jeanphilo Blog</title><link>https://shio-chan-dev.github.io/jeanblog/zh/tags/%E5%90%8E%E5%BA%8F%E9%81%8D%E5%8E%86/</link><description>Recent content in 后序遍历 on Jeanphilo Blog</description><generator>Hugo -- 0.161.1</generator><language>zh-cn</language><lastBuildDate>Mon, 20 Apr 2026 09:37:25 +0800</lastBuildDate><atom:link href="https://shio-chan-dev.github.io/jeanblog/zh/tags/%E5%90%8E%E5%BA%8F%E9%81%8D%E5%8E%86/index.xml" rel="self" type="application/rss+xml"/><item><title>Hot100：二叉树中的最大路径和（Binary Tree Maximum Path Sum）树形 DP / 单边贡献 ACERS 解析</title><link>https://shio-chan-dev.github.io/jeanblog/zh/alg/leetcode/hot100/binary-tree/124-binary-tree-maximum-path-sum/</link><pubDate>Mon, 20 Apr 2026 09:37:25 +0800</pubDate><guid>https://shio-chan-dev.github.io/jeanblog/zh/alg/leetcode/hot100/binary-tree/124-binary-tree-maximum-path-sum/</guid><description>围绕 LeetCode 124 讲清最大路径和的关键设计：递归向上只返回单边贡献，而经过当前节点的完整路径用来更新全局答案。</description></item><item><title>Hot100：二叉树的直径（Diameter of Binary Tree）树形 DP / 高度回传 ACERS 解析</title><link>https://shio-chan-dev.github.io/jeanblog/zh/alg/leetcode/hot100/binary-tree/543-diameter-of-binary-tree/</link><pubDate>Sun, 19 Apr 2026 14:52:28 +0800</pubDate><guid>https://shio-chan-dev.github.io/jeanblog/zh/alg/leetcode/hot100/binary-tree/543-diameter-of-binary-tree/</guid><description>围绕 LeetCode 543 讲清二叉树直径的核心：递归返回高度、在当前节点更新全局直径，以及为什么最长路径不一定只看根到叶。</description></item><item><title>Hot100：二叉树的最近公共祖先（Lowest Common Ancestor of a Binary Tree）后序返回值语义 ACERS 解析</title><link>https://shio-chan-dev.github.io/jeanblog/zh/alg/leetcode/hot100/binary-tree/236-lowest-common-ancestor-of-a-binary-tree/</link><pubDate>Sun, 19 Apr 2026 14:52:28 +0800</pubDate><guid>https://shio-chan-dev.github.io/jeanblog/zh/alg/leetcode/hot100/binary-tree/236-lowest-common-ancestor-of-a-binary-tree/</guid><description>围绕 LeetCode 236 讲清最近公共祖先的后序返回值语义：子树返回什么、什么时候当前节点成为答案、以及为什么节点自己也可以是祖先。</description></item></channel></rss>