Upper Bound

Subtitle / Summary This problem is a useful bridge between sorting and binary search. After sorting the array, all copies of target become one contiguous block, and the answer is simply every index inside that block. Reading time: 10-12 min Tags: sorting, binary search, range location SEO keywords: Find Target Indices After Sorting Array, LeetCode 2089, lower bound, upper bound Meta description: Sort the array, use lower and upper bounds to find the target block, and return every matching index, with tradeoffs, engineering scenarios, and runnable implementations in six languages. Target Readers Learners connecting sorting with lower/upper bound search Engineers who need all positions of one value after offline sorting Interview candidates reviewing how contiguous blocks form in sorted data Background / Motivation The input array is not sorted, so we cannot apply binary search immediately. But once we sort it, every copy of the same value becomes one continuous segment. ...

Subtitle / Summary This problem is a compact exercise in boundary counting. Because the array is already sorted, you do not count negatives and positives one by one; you find where zero starts and where zero ends, then compute both counts from those boundaries. Reading time: 10-12 min Tags: binary search, counting, sorted array, boundaries SEO keywords: Maximum Count of Positive Integer and Negative Integer, LeetCode 2529, boundary counting Meta description: Use lower-bound and upper-bound binary search around zero to count negatives and positives in a sorted array, with correctness reasoning, engineering scenarios, and runnable implementations in six languages. Target Readers Learners practicing boundary search beyond exact-match lookup Engineers who count segments in sorted data Interview candidates learning how lower and upper bounds produce counts Background / Motivation The input is already sorted. That changes the problem completely. ...

Subtitle / Summary This problem is the standard upgrade from “find one target” to “find the whole target block.” The clean solution is not a special-case binary search, but two boundary searches: lower bound for the start and upper bound for the end. Reading time: 12-14 min Tags: binary search, lower bound, upper bound, range query SEO keywords: Search Range, lower bound, upper bound, LeetCode 34 Meta description: Use lower-bound and upper-bound binary search to find the first and last positions of a target in a sorted array, with pitfalls, engineering scenarios, and runnable implementations in six languages. Target Readers Learners who already know basic binary search but struggle with boundary problems Engineers who query sorted logs, timestamps, or grouped IDs Interview candidates who want one reusable range-search template Background / Motivation Finding a single target in a sorted array is the easy version. Real systems often need the full range: ...

Subtitle / Summary This problem is a textbook upper-bound search with one extra twist: wrap-around. Once you can find the first character > target, the rest is just handling the “no answer inside the array” case by returning the first element. Reading time: 10-12 min Tags: binary search, upper bound, characters, wrap-around SEO keywords: Find Smallest Letter Greater Than Target, upper bound, LeetCode 744 Meta description: Use upper-bound binary search and wrap-around handling to solve LeetCode 744, with correctness reasoning, pitfalls, engineering scenarios, and runnable code in six languages. Target Readers Learners who already know lower bound and want to master upper bound Engineers who search the next greater value in a sorted cyclic list Interview candidates practicing boundary-style binary search Background / Motivation At first glance, this looks like a character problem. It is actually a boundary problem: ...