LeetCode 2089: Find Target Indices After Sorting Array ACERS Guide
Subtitle / Summary This problem is a useful bridge between sorting and binary search. After sorting the array, all copies of target become one contiguous block, and the answer is simply every index inside that block. Reading time: 10-12 min Tags: sorting, binary search, range location SEO keywords: Find Target Indices After Sorting Array, LeetCode 2089, lower bound, upper bound Meta description: Sort the array, use lower and upper bounds to find the target block, and return every matching index, with tradeoffs, engineering scenarios, and runnable implementations in six languages. Target Readers Learners connecting sorting with lower/upper bound search Engineers who need all positions of one value after offline sorting Interview candidates reviewing how contiguous blocks form in sorted data Background / Motivation The input array is not sorted, so we cannot apply binary search immediately. But once we sort it, every copy of the same value becomes one continuous segment. ...