Leetcode

Subtitle / Summary If 39. Combination Sum teaches “reuse is allowed”, then 40. Combination Sum II teaches the next real upgrade: duplicate values exist, each number may be used at most once, and de-duplication must happen at the correct tree level. Reading time: 14-16 min Tags: backtracking, dedup, pruning, combination search SEO keywords: Combination Sum II, backtracking, same-layer dedup, pruning, LeetCode 40 Meta description: Build the stable solution for LeetCode 40 from scratch by understanding sorted pruning, use-once recursion, and the same-layer duplicate skip rule. A — Algorithm Problem Restatement Given a collection of candidate numbers candidates and a target integer target, return all unique combinations where the chosen numbers sum to target. ...

Subtitle / Summary Combination Sum is the first Hot100 backtracking problem that really mixes three ideas at once: combination-style search, a running target, and safe pruning after sorting. The point is not to jump straight to the template, but to build it step by step from the problem itself. Reading time: 14-16 min Tags: Hot100, backtracking, combination sum, pruning SEO keywords: Combination Sum, backtracking, pruning, remain, DFS Meta description: Learn LeetCode 39 by building the solution from scratch, using path, remain, repeated candidate reuse, and sorted pruning. A — Algorithm Problem Restatement Given an array of distinct integers candidates and a target integer target, return a list of all unique combinations of candidates where the chosen numbers sum to target. ...

Subtitle / Summary If Subsets teaches the skeleton of combination-style backtracking, Permutations teaches the core of state-based backtracking: at each position, choose one unused element, continue until the path length reaches n, and only then collect the answer. Reading time: 10-12 min Tags: Hot100, backtracking, permutations, DFS SEO keywords: Permutations, backtracking, used array, DFS, LeetCode 46 Meta description: Learn the stable permutation backtracking template for LeetCode 46, with state recovery, engineering analogies, and runnable multi-language solutions. A — Algorithm Problem Restatement Given an array nums of distinct integers, return all possible permutations. The answer may be returned in any order. ...

Subtitle / Summary Clone Graph is not a traversal-only problem. The real challenge is preserving graph structure while avoiding duplicate copies in the presence of cycles. The stable solution is a traversal plus a hash map from original nodes to cloned nodes. Reading time: 12-15 min Tags: graph, dfs, bfs, hash map, deep copy SEO keywords: Clone Graph, graph deep copy, DFS, BFS, LeetCode 133 Meta description: Deep-copy an undirected graph with a node-to-node map, explaining why memoization is mandatory and how DFS/BFS versions work, with runnable code in six languages. Target Readers LeetCode learners practicing graph traversal and deep-copy patterns Engineers who duplicate object graphs, workflow graphs, or topology graphs Developers who want one reusable template for “clone with cycles” Background / Motivation Many “copy” problems are actually identity-preservation problems. ...

Subtitle / Summary This problem is a useful bridge between sorting and binary search. After sorting the array, all copies of target become one contiguous block, and the answer is simply every index inside that block. Reading time: 10-12 min Tags: sorting, binary search, range location SEO keywords: Find Target Indices After Sorting Array, LeetCode 2089, lower bound, upper bound Meta description: Sort the array, use lower and upper bounds to find the target block, and return every matching index, with tradeoffs, engineering scenarios, and runnable implementations in six languages. Target Readers Learners connecting sorting with lower/upper bound search Engineers who need all positions of one value after offline sorting Interview candidates reviewing how contiguous blocks form in sorted data Background / Motivation The input array is not sorted, so we cannot apply binary search immediately. But once we sort it, every copy of the same value becomes one continuous segment. ...

Subtitle / Summary This problem is a compact exercise in boundary counting. Because the array is already sorted, you do not count negatives and positives one by one; you find where zero starts and where zero ends, then compute both counts from those boundaries. Reading time: 10-12 min Tags: binary search, counting, sorted array, boundaries SEO keywords: Maximum Count of Positive Integer and Negative Integer, LeetCode 2529, boundary counting Meta description: Use lower-bound and upper-bound binary search around zero to count negatives and positives in a sorted array, with correctness reasoning, engineering scenarios, and runnable implementations in six languages. Target Readers Learners practicing boundary search beyond exact-match lookup Engineers who count segments in sorted data Interview candidates learning how lower and upper bounds produce counts Background / Motivation The input is already sorted. That changes the problem completely. ...

Subtitle / Summary This problem is the standard upgrade from “find one target” to “find the whole target block.” The clean solution is not a special-case binary search, but two boundary searches: lower bound for the start and upper bound for the end. Reading time: 12-14 min Tags: binary search, lower bound, upper bound, range query SEO keywords: Search Range, lower bound, upper bound, LeetCode 34 Meta description: Use lower-bound and upper-bound binary search to find the first and last positions of a target in a sorted array, with pitfalls, engineering scenarios, and runnable implementations in six languages. Target Readers Learners who already know basic binary search but struggle with boundary problems Engineers who query sorted logs, timestamps, or grouped IDs Interview candidates who want one reusable range-search template Background / Motivation Finding a single target in a sorted array is the easy version. Real systems often need the full range: ...

Subtitle / Summary Search Insert Position is the cleanest lower-bound problem in LeetCode. If you can reliably find the first index where nums[i] >= target, you already have the core template for insert positions, range starts, and many boundary-search problems. Reading time: 10-12 min Tags: binary search, lower bound, sorted array SEO keywords: Search Insert Position, lower bound, binary search, LeetCode 35 Meta description: Lower-bound binary search for Search Insert Position, with boundary reasoning, pitfalls, engineering scenarios, and runnable implementations in Python, C, C++, Go, Rust, and JavaScript. Target Readers Learners who know basic binary search but still hesitate on boundary handling Engineers who insert or locate values in sorted tables Interview candidates who want one reusable lower-bound template Background / Motivation This problem looks simple because the output is a single index. The real lesson is deeper: ...

Subtitle / Summary This problem is a textbook upper-bound search with one extra twist: wrap-around. Once you can find the first character > target, the rest is just handling the “no answer inside the array” case by returning the first element. Reading time: 10-12 min Tags: binary search, upper bound, characters, wrap-around SEO keywords: Find Smallest Letter Greater Than Target, upper bound, LeetCode 744 Meta description: Use upper-bound binary search and wrap-around handling to solve LeetCode 744, with correctness reasoning, pitfalls, engineering scenarios, and runnable code in six languages. Target Readers Learners who already know lower bound and want to master upper bound Engineers who search the next greater value in a sorted cyclic list Interview candidates practicing boundary-style binary search Background / Motivation At first glance, this looks like a character problem. It is actually a boundary problem: ...

Subtitle / Summary Level order traversal is the entry point of the binary-tree BFS template. The real key is not merely “use a queue”, but “separate one level from the next correctly”. This ACERS guide explains the level-size pattern, the DFS depth-bucket alternative, and engineering situations where grouped-by-depth traversal is useful. Reading time: 10-12 min Tags: Hot100, binary tree, BFS, DFS, queue, level order traversal SEO keywords: Hot100, Binary Tree Level Order Traversal, BFS, queue, level order traversal, LeetCode 102 Meta description: A systematic guide to LeetCode 102 from level-by-level BFS to DFS depth buckets, with engineering scenarios and runnable multi-language implementations. Target Readers Hot100 learners who want to make the BFS tree template stable Developers who can traverse a tree but still mix up current-level and next-level boundaries Engineers who need to group tree-shaped data by depth for display or execution Background / Motivation LeetCode 102 is one of the most standard tree-BFS starter problems. ...